Solve 25y^2-10x=-1

$$25 { y }^{ 2 } -10x=-1$$

Solve for x

$$x=\frac{5y^{2}}{2}+\frac{1}{10}$$

Steps for Solving Linear Equation

Subtract 25y^{2} from both sides.

$$-10x=-1-25y^{2}$$

The equation is in standard form.

$$-10x=-25y^{2}-1$$

Divide both sides by -10.

$$\frac{-10x}{-10}=\frac{-25y^{2}-1}{-10}$$

Dividing by -10 undoes the multiplication by -10.

$$x=\frac{-25y^{2}-1}{-10}$$

Divide -1-25y^{2} by -10.

$$x=\frac{5y^{2}}{2}+\frac{1}{10}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{10x-1}}{5}$$

$$y=\frac{\sqrt{10x-1}}{5}$$

Solve for y

$$y=\frac{\sqrt{10x-1}}{5}$$

$$y=-\frac{\sqrt{10x-1}}{5}\text{, }x\geq \frac{1}{10}$$