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\frac{125x^{3}-1}{5}
Factor out \frac{1}{5}.
\left(5x-1\right)\left(25x^{2}+5x+1\right)
Consider 125x^{3}-1. Rewrite 125x^{3}-1 as \left(5x\right)^{3}-1^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
\frac{\left(5x-1\right)\left(25x^{2}+5x+1\right)}{5}
Rewrite the complete factored expression. Polynomial 25x^{2}+5x+1 is not factored since it does not have any rational roots.