Solve 25sqrt{15-8}+12*8^2-left(7^2right)^8

$$25 \sqrt{ 15-8 } +12 \times { 8 }^{ 2 } - { \left( { 7 }^{ 2 } \right) }^{ 8 }$$

Evaluate

$$25\sqrt{7}-33232930568833\approx -3.323293057 \cdot 10^{13}$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 8 to get 16.

$$25\sqrt{15-8}+12\times 8^{2}-7^{16}$$

Subtract 8 from 15 to get 7.

$$25\sqrt{7}+12\times 8^{2}-7^{16}$$

Calculate 8 to the power of 2 and get 64.

$$25\sqrt{7}+12\times 64-7^{16}$$

Multiply 12 and 64 to get 768.

$$25\sqrt{7}+768-7^{16}$$

Calculate 7 to the power of 16 and get 33232930569601.

$$25\sqrt{7}+768-33232930569601$$

Subtract 33232930569601 from 768 to get -33232930568833.

$$25\sqrt{7}-33232930568833$$