Solve 251/2+181/5

$$25 \frac { 1 } { 2 } + 18 \frac { 1 } { 5 }$$

Evaluate

$$\frac{437}{10}=43.7$$

Solution Steps

Multiply 25 and 2 to get 50.

$$\frac{50+1}{2}+\frac{18\times 5+1}{5}$$

Add 50 and 1 to get 51.

$$\frac{51}{2}+\frac{18\times 5+1}{5}$$

Multiply 18 and 5 to get 90.

$$\frac{51}{2}+\frac{90+1}{5}$$

Add 90 and 1 to get 91.

$$\frac{51}{2}+\frac{91}{5}$$

Least common multiple of 2 and 5 is 10. Convert \frac{51}{2} and \frac{91}{5} to fractions with denominator 10.

$$\frac{255}{10}+\frac{182}{10}$$

Since \frac{255}{10} and \frac{182}{10} have the same denominator, add them by adding their numerators.

$$\frac{255+182}{10}$$

Add 255 and 182 to get 437.

$$\frac{437}{10}$$

Factor

$$\frac{19 \cdot 23}{2 \cdot 5} = 43\frac{7}{10} = 43.7$$