Solve 25%x+8%(1-x)=188%

$$25 \% x + 8 \% ( 1 - x ) = 188 \%$$

Solve for x

$$x = \frac{180}{17} = 10\frac{10}{17} \approx 10.588235294$$

Steps for Solving Linear Equation

Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$\frac{1}{4}x+\frac{8}{100}\left(1-x\right)=\frac{188}{100}$$

Reduce the fraction \frac{8}{100} to lowest terms by extracting and canceling out 4.

$$\frac{1}{4}x+\frac{2}{25}\left(1-x\right)=\frac{188}{100}$$

Use the distributive property to multiply \frac{2}{25} by 1-x.

$$\frac{1}{4}x+\frac{2}{25}+\frac{2}{25}\left(-1\right)x=\frac{188}{100}$$

Multiply \frac{2}{25} and -1 to get -\frac{2}{25}.

$$\frac{1}{4}x+\frac{2}{25}-\frac{2}{25}x=\frac{188}{100}$$

Combine \frac{1}{4}x and -\frac{2}{25}x to get \frac{17}{100}x.

$$\frac{17}{100}x+\frac{2}{25}=\frac{188}{100}$$

Reduce the fraction \frac{188}{100} to lowest terms by extracting and canceling out 4.

$$\frac{17}{100}x+\frac{2}{25}=\frac{47}{25}$$

Subtract \frac{2}{25} from both sides.

$$\frac{17}{100}x=\frac{47}{25}-\frac{2}{25}$$

Since \frac{47}{25} and \frac{2}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17}{100}x=\frac{47-2}{25}$$

Subtract 2 from 47 to get 45.

$$\frac{17}{100}x=\frac{45}{25}$$

Reduce the fraction \frac{45}{25} to lowest terms by extracting and canceling out 5.

$$\frac{17}{100}x=\frac{9}{5}$$

Multiply both sides by \frac{100}{17}, the reciprocal of \frac{17}{100}.

$$x=\frac{9}{5}\times \frac{100}{17}$$

Multiply \frac{9}{5} times \frac{100}{17} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{9\times 100}{5\times 17}$$

Do the multiplications in the fraction \frac{9\times 100}{5\times 17}.

$$x=\frac{900}{85}$$

Reduce the fraction \frac{900}{85} to lowest terms by extracting and canceling out 5.

$$x=\frac{180}{17}$$