Solve 25^2-35^2+19^2=2*29*9+81

$$25 ^ { 2 } - 35 ^ { 2 } + 19 ^ { 2 } = 2 \cdot 29 \cdot 9 + 81$$

Verify

Solution Steps

Calculate 25 to the power of 2 and get 625.

$$625-35^{2}+19^{2}=2\times 29\times 9+81$$

Calculate 35 to the power of 2 and get 1225.

$$625-1225+19^{2}=2\times 29\times 9+81$$

Subtract 1225 from 625 to get -600.

$$-600+19^{2}=2\times 29\times 9+81$$

Calculate 19 to the power of 2 and get 361.

$$-600+361=2\times 29\times 9+81$$

Add -600 and 361 to get -239.

$$-239=2\times 29\times 9+81$$

Multiply 2 and 29 to get 58.

$$-239=58\times 9+81$$

Multiply 58 and 9 to get 522.

$$-239=522+81$$

Add 522 and 81 to get 603.

$$-239=603$$

Compare -239 and 603.

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