Solve 25^2+[(6-3/4)div2]*2^5

$$25 ^ { 2 } + [ ( 6 - \frac { 3 } { 4 } ) \div 2 ] \times 2 ^ { 5 }$$

Evaluate

$$709$$

Solution Steps

Calculate 25 to the power of 2 and get 625.

$$625+\frac{6-\frac{3}{4}}{2}\times 2^{5}$$

Convert 6 to fraction \frac{24}{4}.

$$625+\frac{\frac{24}{4}-\frac{3}{4}}{2}\times 2^{5}$$

Since \frac{24}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$625+\frac{\frac{24-3}{4}}{2}\times 2^{5}$$

Subtract 3 from 24 to get 21.

$$625+\frac{\frac{21}{4}}{2}\times 2^{5}$$

Express \frac{\frac{21}{4}}{2} as a single fraction.

$$625+\frac{21}{4\times 2}\times 2^{5}$$

Multiply 4 and 2 to get 8.

$$625+\frac{21}{8}\times 2^{5}$$

Calculate 2 to the power of 5 and get 32.

$$625+\frac{21}{8}\times 32$$

Express \frac{21}{8}\times 32 as a single fraction.

$$625+\frac{21\times 32}{8}$$

Multiply 21 and 32 to get 672.

$$625+\frac{672}{8}$$

Divide 672 by 8 to get 84.

$$625+84$$

Add 625 and 84 to get 709.

$$709$$

Factor

$$709$$