Solve 25+y^2-4y+4=9+y^2-8y-16

$$25 + y ^ { 2 } - 4 y + 4 = 9 + y ^ { 2 } - 8 y - 16$$

Solve for y

$$y=-9$$

Steps for Solving Linear Equation

Add 25 and 4 to get 29.

$$29+y^{2}-4y=9+y^{2}-8y-16$$

Subtract 16 from 9 to get -7.

$$29+y^{2}-4y=-7+y^{2}-8y$$

Subtract y^{2} from both sides.

$$29+y^{2}-4y-y^{2}=-7-8y$$

Combine y^{2} and -y^{2} to get 0.

$$29-4y=-7-8y$$

Add 8y to both sides.

$$29-4y+8y=-7$$

Combine -4y and 8y to get 4y.

$$29+4y=-7$$

Subtract 29 from both sides.

$$4y=-7-29$$

Subtract 29 from -7 to get -36.

$$4y=-36$$

Divide both sides by 4.

$$y=\frac{-36}{4}$$

Divide -36 by 4 to get -9.

$$y=-9$$