Solve 25+(16+x^2)=(3+x)^2

$$25 + ( 16 + x ^ { 2 } ) = ( 3 + x ) ^ { 2 }$$

Solve for x

$$x = \frac{16}{3} = 5\frac{1}{3} \approx 5.333333333$$

Steps for Solving Linear Equation

Add 25 and 16 to get 41.

$$41+x^{2}=\left(3+x\right)^{2}$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3+x\right)^{2}.

$$41+x^{2}=9+6x+x^{2}$$

Subtract 6x from both sides.

$$41+x^{2}-6x=9+x^{2}$$

Subtract x^{2} from both sides.

$$41+x^{2}-6x-x^{2}=9$$

Combine x^{2} and -x^{2} to get 0.

$$41-6x=9$$

Subtract 41 from both sides.

$$-6x=9-41$$

Subtract 41 from 9 to get -32.

$$-6x=-32$$

Divide both sides by -6.

$$x=\frac{-32}{-6}$$

Reduce the fraction \frac{-32}{-6} to lowest terms by extracting and canceling out -2.

$$x=\frac{16}{3}$$