Solve 240*(3/10+8/15)

$$240 \times ( \frac{ 3 }{ 10 } + \frac{ 8 }{ 15 } )$$

Evaluate

$$200$$

Solution Steps

Least common multiple of 10 and 15 is 30. Convert \frac{3}{10} and \frac{8}{15} to fractions with denominator 30.

$$240\left(\frac{9}{30}+\frac{16}{30}\right)$$

Since \frac{9}{30} and \frac{16}{30} have the same denominator, add them by adding their numerators.

$$240\times \frac{9+16}{30}$$

Add 9 and 16 to get 25.

$$240\times \frac{25}{30}$$

Reduce the fraction \frac{25}{30} to lowest terms by extracting and canceling out 5.

$$240\times \frac{5}{6}$$

Express 240\times \frac{5}{6} as a single fraction.

$$\frac{240\times 5}{6}$$

Multiply 240 and 5 to get 1200.

$$\frac{1200}{6}$$

Divide 1200 by 6 to get 200.

$$200$$

Factor

$$2^{3}\times 5^{2}$$