Solve 240div10lfloor2+{7*3+2(75-4*13+12div6)}rfloor

$$240 \div 10 \lfloor 2 + \{ 7 \times 3 + 2 ( 75 - 4 \times 13 + 12 \div 6 ) \} \rfloor$$

Evaluate

$$1752$$

Solution Steps

Divide 240 by 10 to get 24.

$$24\lfloor 2+7\times 3+2\left(75-4\times 13+\frac{12}{6}\right)\rfloor$$

Multiply 7 and 3 to get 21.

$$24\lfloor 2+21+2\left(75-4\times 13+\frac{12}{6}\right)\rfloor$$

Add 2 and 21 to get 23.

$$24\lfloor 23+2\left(75-4\times 13+\frac{12}{6}\right)\rfloor$$

Multiply 4 and 13 to get 52.

$$24\lfloor 23+2\left(75-52+\frac{12}{6}\right)\rfloor$$

Subtract 52 from 75 to get 23.

$$24\lfloor 23+2\left(23+\frac{12}{6}\right)\rfloor$$

Divide 12 by 6 to get 2.

$$24\lfloor 23+2\left(23+2\right)\rfloor$$

Add 23 and 2 to get 25.

$$24\lfloor 23+2\times 25\rfloor$$

Multiply 2 and 25 to get 50.

$$24\lfloor 23+50\rfloor$$

Add 23 and 50 to get 73.

$$24\lfloor 73\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 73 is 73.

$$24\times 73$$

Multiply 24 and 73 to get 1752.

$$1752$$

Factor

$$2^{3}\times 3\times 73$$