Solve 240+06x<144x+144

$$240 + 06 x < 144 x + 144$$

Solve for x

$$x>\frac{2}{3}$$

Solution Steps

Multiply 0 and 6 to get 0.

$$240+0x<144x+144$$

Anything times zero gives zero.

$$240+0<144x+144$$

Add 240 and 0 to get 240.

$$240<144x+144$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$144x+144>240$$

Subtract 144 from both sides.

$$144x>240-144$$

Subtract 144 from 240 to get 96.

$$144x>96$$

Divide both sides by 144. Since 144 is positive, the inequality direction remains the same.

$$x>\frac{96}{144}$$

Reduce the fraction \frac{96}{144} to lowest terms by extracting and canceling out 48.

$$x>\frac{2}{3}$$