Solve for x
x\leq \frac{1}{2}
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24+125x-83x\leq 45
Subtract 83x from both sides.
24+42x\leq 45
Combine 125x and -83x to get 42x.
42x\leq 45-24
Subtract 24 from both sides.
42x\leq 21
Subtract 24 from 45 to get 21.
x\leq \frac{21}{42}
Divide both sides by 42. Since 42 is positive, the inequality direction remains the same.
x\leq \frac{1}{2}
Reduce the fraction \frac{21}{42} to lowest terms by extracting and canceling out 21.
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