Solve 24+1/3*3/2-1/3

$$24+ \frac{ 1 }{ 3 } \times \frac{ 3 }{ 2 } - \frac{ 1 }{ 3 }$$

Evaluate

$$\frac{145}{6}\approx 24.166666667$$

Solution Steps

Multiply \frac{1}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$24+\frac{1\times 3}{3\times 2}-\frac{1}{3}$$

Cancel out 3 in both numerator and denominator.

$$24+\frac{1}{2}-\frac{1}{3}$$

Convert 24 to fraction \frac{48}{2}.

$$\frac{48}{2}+\frac{1}{2}-\frac{1}{3}$$

Since \frac{48}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{48+1}{2}-\frac{1}{3}$$

Add 48 and 1 to get 49.

$$\frac{49}{2}-\frac{1}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{49}{2} and \frac{1}{3} to fractions with denominator 6.

$$\frac{147}{6}-\frac{2}{6}$$

Since \frac{147}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{147-2}{6}$$

Subtract 2 from 147 to get 145.

$$\frac{145}{6}$$

Factor

$$\frac{5 \cdot 29}{2 \cdot 3} = 24\frac{1}{6} = 24.166666666666668$$