Solve 24x^2+16xy+8=84

$$24 { x }^{ 2 } +16xy+8=84$$

Solve for y

$$y=-\frac{3x}{2}+\frac{19}{4x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 24x^{2} from both sides.

$$16xy+8=84-24x^{2}$$

Subtract 8 from both sides.

$$16xy=84-24x^{2}-8$$

Subtract 8 from 84 to get 76.

$$16xy=76-24x^{2}$$

Divide both sides by 16x.

$$\frac{16xy}{16x}=\frac{76-24x^{2}}{16x}$$

Dividing by 16x undoes the multiplication by 16x.

$$y=\frac{76-24x^{2}}{16x}$$

Divide 76-24x^{2} by 16x.

$$y=-\frac{3x}{2}+\frac{19}{4x}$$

Solve for x

$$x=\frac{\sqrt{4y^{2}+114}}{6}-\frac{y}{3}$$

$$x=-\frac{\sqrt{4y^{2}+114}}{6}-\frac{y}{3}$$