Solve 24*[(15/6-2/3)*3]

$$24 \times [ ( 1 \frac { 5 } { 6 } - \frac { 2 } { 3 } ) \times 3 ]$$

Evaluate

$$84$$

Solution Steps

Multiply 1 and 6 to get 6.

$$24\left(\frac{6+5}{6}-\frac{2}{3}\right)\times 3$$

Add 6 and 5 to get 11.

$$24\left(\frac{11}{6}-\frac{2}{3}\right)\times 3$$

Least common multiple of 6 and 3 is 6. Convert \frac{11}{6} and \frac{2}{3} to fractions with denominator 6.

$$24\left(\frac{11}{6}-\frac{4}{6}\right)\times 3$$

Since \frac{11}{6} and \frac{4}{6} have the same denominator, subtract them by subtracting their numerators.

$$24\times \frac{11-4}{6}\times 3$$

Subtract 4 from 11 to get 7.

$$24\times \frac{7}{6}\times 3$$

Express 24\times \frac{7}{6} as a single fraction.

$$\frac{24\times 7}{6}\times 3$$

Multiply 24 and 7 to get 168.

$$\frac{168}{6}\times 3$$

Divide 168 by 6 to get 28.

$$28\times 3$$

Multiply 28 and 3 to get 84.

$$84$$

Factor

$$2^{2}\times 3\times 7$$