Solve 24*(11/12-3/4-1/6)

$$24 \cdot ( \frac { 11 } { 12 } - \frac { 3 } { 4 } - \frac { 1 } { 6 } )$$

Evaluate

$$0$$

Solution Steps

Least common multiple of 12 and 4 is 12. Convert \frac{11}{12} and \frac{3}{4} to fractions with denominator 12.

$$24\left(\frac{11}{12}-\frac{9}{12}-\frac{1}{6}\right)$$

Since \frac{11}{12} and \frac{9}{12} have the same denominator, subtract them by subtracting their numerators.

$$24\left(\frac{11-9}{12}-\frac{1}{6}\right)$$

Subtract 9 from 11 to get 2.

$$24\left(\frac{2}{12}-\frac{1}{6}\right)$$

Reduce the fraction \frac{2}{12} to lowest terms by extracting and canceling out 2.

$$24\left(\frac{1}{6}-\frac{1}{6}\right)$$

Subtract \frac{1}{6} from \frac{1}{6} to get 0.

$$24\times 0$$

Multiply 24 and 0 to get 0.

$$0$$

Factor

$$0$$