Solve 24=x^2+4

$$24 = x ^ { 2 } + 4$$

Solve for x

$$x=2\sqrt{5}\approx 4.472135955$$

$$x=-2\sqrt{5}\approx -4.472135955$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+4=24$$

Subtract 4 from both sides.

$$x^{2}=24-4$$

Subtract 4 from 24 to get 20.

$$x^{2}=20$$

Take the square root of both sides of the equation.

$$x=2\sqrt{5} x=-2\sqrt{5}$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+4=24$$

Subtract 24 from both sides.

$$x^{2}+4-24=0$$

Subtract 24 from 4 to get -20.

$$x^{2}-20=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-20\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-20\right)}}{2}$$

Multiply -4 times -20.

$$x=\frac{0±\sqrt{80}}{2}$$

Take the square root of 80.

$$x=\frac{0±4\sqrt{5}}{2}$$

Now solve the equation x=\frac{0±4\sqrt{5}}{2} when ± is plus.

$$x=2\sqrt{5}$$

Now solve the equation x=\frac{0±4\sqrt{5}}{2} when ± is minus.

$$x=-2\sqrt{5}$$

The equation is now solved.

$$x=2\sqrt{5} x=-2\sqrt{5}$$