Solve 234+frac{sqrt{2-1}}{2^3}-8=

$$234 + \frac { \sqrt { 2 - 1 } } { 2 ^ { 3 } } - 8 =$$

Evaluate

$$\frac{1809}{8}=226.125$$

Solution Steps

Subtract 1 from 2 to get 1.

$$234+\frac{\sqrt{1}}{2^{3}}-8$$

Calculate the square root of 1 and get 1.

$$234+\frac{1}{2^{3}}-8$$

Calculate 2 to the power of 3 and get 8.

$$234+\frac{1}{8}-8$$

Convert 234 to fraction \frac{1872}{8}.

$$\frac{1872}{8}+\frac{1}{8}-8$$

Since \frac{1872}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{1872+1}{8}-8$$

Add 1872 and 1 to get 1873.

$$\frac{1873}{8}-8$$

Convert 8 to fraction \frac{64}{8}.

$$\frac{1873}{8}-\frac{64}{8}$$

Since \frac{1873}{8} and \frac{64}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1873-64}{8}$$

Subtract 64 from 1873 to get 1809.

$$\frac{1809}{8}$$

Factor

$$\frac{3 ^ {3} \cdot 67}{2 ^ {3}} = 226\frac{1}{8} = 226.125$$