Solve 232quad8+5^{4}-3^{2}*2^{2}-4^3+10-7^3-13^2-4^2

$$232 \quad 8 + 5 ^ { 4 } - 3 ^ { 2 } \times 2 ^ { 2 } - 4 ^ { 3 } + 10 - 7 ^ { 3 } - 13 ^ { 2 } - 4 ^ { 2 }$$

Evaluate

$$1863$$

Solution Steps

Multiply 232 and 8 to get 1856.

$$1856+5^{4}-3^{2}\times 2^{2}-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Calculate 5 to the power of 4 and get 625.

$$1856+625-3^{2}\times 2^{2}-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Add 1856 and 625 to get 2481.

$$2481-3^{2}\times 2^{2}-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Calculate 3 to the power of 2 and get 9.

$$2481-9\times 2^{2}-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Calculate 2 to the power of 2 and get 4.

$$2481-9\times 4-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Multiply 9 and 4 to get 36.

$$2481-36-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Subtract 36 from 2481 to get 2445.

$$2445-4^{3}+10-7^{3}-13^{2}-4^{2}$$

Calculate 4 to the power of 3 and get 64.

$$2445-64+10-7^{3}-13^{2}-4^{2}$$

Subtract 64 from 2445 to get 2381.

$$2381+10-7^{3}-13^{2}-4^{2}$$

Add 2381 and 10 to get 2391.

$$2391-7^{3}-13^{2}-4^{2}$$

Calculate 7 to the power of 3 and get 343.

$$2391-343-13^{2}-4^{2}$$

Subtract 343 from 2391 to get 2048.

$$2048-13^{2}-4^{2}$$

Calculate 13 to the power of 2 and get 169.

$$2048-169-4^{2}$$

Subtract 169 from 2048 to get 1879.

$$1879-4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$1879-16$$

Subtract 16 from 1879 to get 1863.

$$1863$$

Factor

$$3^{4}\times 23$$