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\frac{\left(23\times 21+1\right)\times 7}{21\left(1\times 7+3\right)}
Divide \frac{23\times 21+1}{21} by \frac{1\times 7+3}{7} by multiplying \frac{23\times 21+1}{21} by the reciprocal of \frac{1\times 7+3}{7}.
\frac{1+21\times 23}{3\left(3+7\right)}
Cancel out 7 in both numerator and denominator.
\frac{1+483}{3\left(3+7\right)}
Multiply 21 and 23 to get 483.
\frac{484}{3\left(3+7\right)}
Add 1 and 483 to get 484.
\frac{484}{3\times 10}
Add 3 and 7 to get 10.
\frac{484}{30}
Multiply 3 and 10 to get 30.
\frac{242}{15}
Reduce the fraction \frac{484}{30} to lowest terms by extracting and canceling out 2.