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225=b^{2}-16b
Use the distributive property to multiply b by b-16.
b^{2}-16b=225
Swap sides so that all variable terms are on the left hand side.
b^{2}-16b-225=0
Subtract 225 from both sides.
b=\frac{-\left(-16\right)±\sqrt{\left(-16\right)^{2}-4\left(-225\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -16 for b, and -225 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
b=\frac{-\left(-16\right)±\sqrt{256-4\left(-225\right)}}{2}
Square -16.
b=\frac{-\left(-16\right)±\sqrt{256+900}}{2}
Multiply -4 times -225.
b=\frac{-\left(-16\right)±\sqrt{1156}}{2}
Add 256 to 900.
b=\frac{-\left(-16\right)±34}{2}
Take the square root of 1156.
b=\frac{16±34}{2}
The opposite of -16 is 16.
b=\frac{50}{2}
Now solve the equation b=\frac{16±34}{2} when ± is plus. Add 16 to 34.
b=25
Divide 50 by 2.
b=-\frac{18}{2}
Now solve the equation b=\frac{16±34}{2} when ± is minus. Subtract 34 from 16.
b=-9
Divide -18 by 2.
b=25 b=-9
The equation is now solved.
225=b^{2}-16b
Use the distributive property to multiply b by b-16.
b^{2}-16b=225
Swap sides so that all variable terms are on the left hand side.
b^{2}-16b+\left(-8\right)^{2}=225+\left(-8\right)^{2}
Divide -16, the coefficient of the x term, by 2 to get -8. Then add the square of -8 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
b^{2}-16b+64=225+64
Square -8.
b^{2}-16b+64=289
Add 225 to 64.
\left(b-8\right)^{2}=289
Factor b^{2}-16b+64. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(b-8\right)^{2}}=\sqrt{289}
Take the square root of both sides of the equation.
b-8=17 b-8=-17
Simplify.
b=25 b=-9
Add 8 to both sides of the equation.