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7\left(32az+8ac-12yz-3yc\right)
Factor out 7.
8a\left(4z+c\right)-3y\left(4z+c\right)
Consider 32az+8ac-12yz-3yc. Do the grouping 32az+8ac-12yz-3yc=\left(32az+8ac\right)+\left(-12yz-3yc\right), and factor out 8a in the first and -3y in the second group.
\left(4z+c\right)\left(8a-3y\right)
Factor out common term 4z+c by using distributive property.
7\left(-3y+8a\right)\left(4z+c\right)
Rewrite the complete factored expression.