Solve 22122/4+45/10=

$$221 \frac { 22 } { 4 } + \frac { 45 } { 10 } =$$

Evaluate

$$231$$

Solution Steps

Multiply 221 and 4 to get 884.

$$\frac{884+22}{4}+\frac{45}{10}$$

Add 884 and 22 to get 906.

$$\frac{906}{4}+\frac{45}{10}$$

Reduce the fraction \frac{906}{4} to lowest terms by extracting and canceling out 2.

$$\frac{453}{2}+\frac{45}{10}$$

Reduce the fraction \frac{45}{10} to lowest terms by extracting and canceling out 5.

$$\frac{453}{2}+\frac{9}{2}$$

Since \frac{453}{2} and \frac{9}{2} have the same denominator, add them by adding their numerators.

$$\frac{453+9}{2}$$

Add 453 and 9 to get 462.

$$\frac{462}{2}$$

Divide 462 by 2 to get 231.

$$231$$

Factor

$$3\times 7\times 11$$