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2200t^{2}-100t-1500=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
t=\frac{-\left(-100\right)±\sqrt{\left(-100\right)^{2}-4\times 2200\left(-1500\right)}}{2\times 2200}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2200 for a, -100 for b, and -1500 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{-\left(-100\right)±\sqrt{10000-4\times 2200\left(-1500\right)}}{2\times 2200}
Square -100.
t=\frac{-\left(-100\right)±\sqrt{10000-8800\left(-1500\right)}}{2\times 2200}
Multiply -4 times 2200.
t=\frac{-\left(-100\right)±\sqrt{10000+13200000}}{2\times 2200}
Multiply -8800 times -1500.
t=\frac{-\left(-100\right)±\sqrt{13210000}}{2\times 2200}
Add 10000 to 13200000.
t=\frac{-\left(-100\right)±100\sqrt{1321}}{2\times 2200}
Take the square root of 13210000.
t=\frac{100±100\sqrt{1321}}{2\times 2200}
The opposite of -100 is 100.
t=\frac{100±100\sqrt{1321}}{4400}
Multiply 2 times 2200.
t=\frac{100\sqrt{1321}+100}{4400}
Now solve the equation t=\frac{100±100\sqrt{1321}}{4400} when ± is plus. Add 100 to 100\sqrt{1321}.
t=\frac{\sqrt{1321}+1}{44}
Divide 100+100\sqrt{1321} by 4400.
t=\frac{100-100\sqrt{1321}}{4400}
Now solve the equation t=\frac{100±100\sqrt{1321}}{4400} when ± is minus. Subtract 100\sqrt{1321} from 100.
t=\frac{1-\sqrt{1321}}{44}
Divide 100-100\sqrt{1321} by 4400.
t=\frac{\sqrt{1321}+1}{44} t=\frac{1-\sqrt{1321}}{44}
The equation is now solved.
2200t^{2}-100t-1500=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
2200t^{2}-100t-1500-\left(-1500\right)=-\left(-1500\right)
Add 1500 to both sides of the equation.
2200t^{2}-100t=-\left(-1500\right)
Subtracting -1500 from itself leaves 0.
2200t^{2}-100t=1500
Subtract -1500 from 0.
\frac{2200t^{2}-100t}{2200}=\frac{1500}{2200}
Divide both sides by 2200.
t^{2}+\left(-\frac{100}{2200}\right)t=\frac{1500}{2200}
Dividing by 2200 undoes the multiplication by 2200.
t^{2}-\frac{1}{22}t=\frac{1500}{2200}
Reduce the fraction \frac{-100}{2200} to lowest terms by extracting and canceling out 100.
t^{2}-\frac{1}{22}t=\frac{15}{22}
Reduce the fraction \frac{1500}{2200} to lowest terms by extracting and canceling out 100.
t^{2}-\frac{1}{22}t+\left(-\frac{1}{44}\right)^{2}=\frac{15}{22}+\left(-\frac{1}{44}\right)^{2}
Divide -\frac{1}{22}, the coefficient of the x term, by 2 to get -\frac{1}{44}. Then add the square of -\frac{1}{44} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
t^{2}-\frac{1}{22}t+\frac{1}{1936}=\frac{15}{22}+\frac{1}{1936}
Square -\frac{1}{44} by squaring both the numerator and the denominator of the fraction.
t^{2}-\frac{1}{22}t+\frac{1}{1936}=\frac{1321}{1936}
Add \frac{15}{22} to \frac{1}{1936} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(t-\frac{1}{44}\right)^{2}=\frac{1321}{1936}
Factor t^{2}-\frac{1}{22}t+\frac{1}{1936}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(t-\frac{1}{44}\right)^{2}}=\sqrt{\frac{1321}{1936}}
Take the square root of both sides of the equation.
t-\frac{1}{44}=\frac{\sqrt{1321}}{44} t-\frac{1}{44}=-\frac{\sqrt{1321}}{44}
Simplify.
t=\frac{\sqrt{1321}+1}{44} t=\frac{1-\sqrt{1321}}{44}
Add \frac{1}{44} to both sides of the equation.
x ^ 2 -\frac{1}{22}x -\frac{15}{22} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 2200
r + s = \frac{1}{22} rs = -\frac{15}{22}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{1}{44} - u s = \frac{1}{44} + u
Two numbers r and s sum up to \frac{1}{22} exactly when the average of the two numbers is \frac{1}{2}*\frac{1}{22} = \frac{1}{44}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{1}{44} - u) (\frac{1}{44} + u) = -\frac{15}{22}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{15}{22}
\frac{1}{1936} - u^2 = -\frac{15}{22}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{15}{22}-\frac{1}{1936} = -\frac{1321}{1936}
Simplify the expression by subtracting \frac{1}{1936} on both sides
u^2 = \frac{1321}{1936} u = \pm\sqrt{\frac{1321}{1936}} = \pm \frac{\sqrt{1321}}{44}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{1}{44} - \frac{\sqrt{1321}}{44} = -0.803 s = \frac{1}{44} + \frac{\sqrt{1321}}{44} = 0.849
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.