Solve 22x^2-342c_{1}+2211^3=0

$$22 x ^ { 2 } - 342 c _ { 1 } + 2211 ^ { 3 } = 0$$

Solve for c_1

$$c_{1}=\frac{11x^{2}}{171}+\frac{1200946659}{38}$$

Steps for Solving Linear Equation

Calculate 2211 to the power of 3 and get 10808519931.

$$22x^{2}-342c_{1}[phone]=0$$

Subtract 22x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-342c_{1}[phone]=-22x^{2}$$

Subtract 10808519931 from both sides.

$$-342c_{1}=-22x^{2}-10808519931$$

Divide both sides by -342.

$$\frac{-342c_{1}}{-342}=\frac{-22x^{2}-10808519931}{-342}$$

Dividing by -342 undoes the multiplication by -342.

$$c_{1}=\frac{-22x^{2}-10808519931}{-342}$$

Divide -22x^{2}-10808519931 by -342.

$$c_{1}=\frac{11x^{2}}{171}+\frac{1200946659}{38}$$

Solve for x (complex solution)

$$x=-\frac{3\sqrt{836c_{1}-26420826498}}{22}$$

$$x=\frac{3\sqrt{836c_{1}-26420826498}}{22}$$

Solve for x

$$x=\frac{3\sqrt{836c_{1}-26420826498}}{22}$$

$$x=-\frac{3\sqrt{836c_{1}-26420826498}}{22}\text{, }c_{1}\geq \frac{1200946659}{38}$$