Solve 21xdiv7={left(sqrt{x*2}right)}^2

$$21x \div 7= { \left( \sqrt{ x \times 2 } \right) }^{ 2 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 7.

$$21x=7\left(\sqrt{x\times 2}\right)^{2}$$

Calculate \sqrt{x\times 2} to the power of 2 and get x\times 2.

$$21x=7x\times 2$$

Multiply 7 and 2 to get 14.

$$21x=14x$$

Subtract 14x from both sides.

$$21x-14x=0$$

Combine 21x and -14x to get 7x.

$$7x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 7 is not equal to 0, x must be equal to 0.

$$x=0$$