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\left(-5x+6y^{2}\right)\left(25x^{2}+30xy^{2}+36y^{4}\right)
Rewrite 216y^{6}-125x^{3} as \left(-5x\right)^{3}+\left(6y^{2}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).