Factor
8\left(y+3\right)\left(y^{2}-3y+9\right)
Evaluate
8\left(y^{3}+27\right)
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8\left(27+y^{3}\right)
Factor out 8.
\left(y+3\right)\left(y^{2}-3y+9\right)
Consider 27+y^{3}. Rewrite 27+y^{3} as y^{3}+3^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
8\left(y+3\right)\left(y^{2}-3y+9\right)
Rewrite the complete factored expression. Polynomial y^{2}-3y+9 is not factored since it does not have any rational roots.
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