Solve 2113=1/2s_{1}[B+(B-12)]

$$2113 = \frac { 1 } { 2 } s _ { 1 } [ B + ( B - 12 ) ]$$

Solve for B

$$B=6+\frac{2113}{s_{1}}$$

$$s_{1}\neq 0$$

Steps for Solving Linear Equation

Combine B and B to get 2B.

$$2113=\frac{1}{2}s_{1}\left(2B-12\right)$$

Use the distributive property to multiply \frac{1}{2}s_{1} by 2B-12.

$$2113=s_{1}B-6s_{1}$$

Swap sides so that all variable terms are on the left hand side.

$$s_{1}B-6s_{1}=2113$$

Add 6s_{1} to both sides.

$$s_{1}B=2113+6s_{1}$$

The equation is in standard form.

$$s_{1}B=6s_{1}+2113$$

Divide both sides by s_{1}.

$$\frac{s_{1}B}{s_{1}}=\frac{6s_{1}+2113}{s_{1}}$$

Dividing by s_{1} undoes the multiplication by s_{1}.

$$B=\frac{6s_{1}+2113}{s_{1}}$$

Divide 2113+6s_{1} by s_{1}.

$$B=6+\frac{2113}{s_{1}}$$

Solve for s_1

$$s_{1}=-\frac{2113}{6-B}$$

$$B\neq 6$$

Steps for Solving Linear Equation

Combine B and B to get 2B.

$$2113=\frac{1}{2}s_{1}\left(2B-12\right)$$

Use the distributive property to multiply \frac{1}{2}s_{1} by 2B-12.

$$2113=s_{1}B-6s_{1}$$

Swap sides so that all variable terms are on the left hand side.

$$s_{1}B-6s_{1}=2113$$

Combine all terms containing s_{1}.

$$\left(B-6\right)s_{1}=2113$$

Divide both sides by B-6.

$$\frac{\left(B-6\right)s_{1}}{B-6}=\frac{2113}{B-6}$$

Dividing by B-6 undoes the multiplication by B-6.

$$s_{1}=\frac{2113}{B-6}$$