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21q^{2}\left(q-1\right)+10\left(q-1\right)
Do the grouping 21q^{3}-21q^{2}+10q-10=\left(21q^{3}-21q^{2}\right)+\left(10q-10\right), and factor out 21q^{2} in the first and 10 in the second group.
\left(q-1\right)\left(21q^{2}+10\right)
Factor out common term q-1 by using distributive property. Polynomial 21q^{2}+10 is not factored since it does not have any rational roots.