Solve 21bdiv(-3/2)=

$$21 b \div ( - \frac { 3 } { 2 } ) =$$

Evaluate

$$-14b$$

Solution Steps

Divide 21b by -\frac{3}{2} by multiplying 21b by the reciprocal of -\frac{3}{2}.

$$\frac{21b\times 2}{-3}$$

Multiply 21 and 2 to get 42.

$$\frac{42b}{-3}$$

Divide 42b by -3 to get -14b.

$$-14b$$

Differentiate w.r.t. b

$$-14$$

Steps Using Definition of a Derivative

Divide 21b by -\frac{3}{2} by multiplying 21b by the reciprocal of -\frac{3}{2}.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{21b\times 2}{-3})$$

Multiply 21 and 2 to get 42.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{42b}{-3})$$

Divide 42b by -3 to get -14b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-14b)$$

The derivative of ax^{n} is nax^{n-1}.

$$-14b^{1-1}$$

Subtract 1 from 1.

$$-14b^{0}$$

For any term t except 0, t^{0}=1.

$$-14$$