Solve 21a^3x^4b^2div7ax^2b

$$21 { a }^{ 3 } { x }^{ 4 } { b }^{ 2 } \div 7a { x }^{ 2 } b$$

Evaluate

$$3b^{3}a^{4}x^{6}$$

Solution Steps

Divide 21a^{3}x^{4}b^{2} by 7 to get 3a^{3}x^{4}b^{2}.

$$3a^{3}x^{4}b^{2}ax^{2}b$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$3a^{4}x^{4}b^{2}x^{2}b$$

To multiply powers of the same base, add their exponents. Add 4 and 2 to get 6.

$$3a^{4}x^{6}b^{2}b$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$3a^{4}x^{6}b^{3}$$

Differentiate w.r.t. x

$$18b^{3}a^{4}x^{5}$$