Solve 21div4/8=2^2x

$$21 \div \frac { 4 } { 8 } = 2 ^ { 2 } x$$

Solve for x

$$x = \frac{21}{2} = 10\frac{1}{2} = 10.5$$

Steps for Solving Linear Equation

Divide 21 by \frac{4}{8} by multiplying 21 by the reciprocal of \frac{4}{8}.

$$\frac{21\times 8}{4}=2^{2}x$$

Multiply 21 and 8 to get 168.

$$\frac{168}{4}=2^{2}x$$

Divide 168 by 4 to get 42.

$$42=2^{2}x$$

Calculate 2 to the power of 2 and get 4.

$$42=4x$$

Swap sides so that all variable terms are on the left hand side.

$$4x=42$$

Divide both sides by 4.

$$x=\frac{42}{4}$$

Reduce the fraction \frac{42}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{21}{2}$$