Solve 21div12100+63div6050+63div2420+21div605=

$$21 \div 12100+63 \div 6050+63 \div 2420+21 \div 605=$$

Evaluate

$$\frac{441}{6050}\approx 0.072892562$$

Solution Steps

Least common multiple of 12100 and 6050 is 12100. Convert \frac{21}{12100} and \frac{63}{6050} to fractions with denominator 12100.

$$\frac{21}{12100}+\frac{126}{12100}+\frac{63}{2420}+\frac{21}{605}$$

Since \frac{21}{12100} and \frac{126}{12100} have the same denominator, add them by adding their numerators.

$$\frac{21+126}{12100}+\frac{63}{2420}+\frac{21}{605}$$

Add 21 and 126 to get 147.

$$\frac{147}{12100}+\frac{63}{2420}+\frac{21}{605}$$

Least common multiple of 12100 and 2420 is 12100. Convert \frac{147}{12100} and \frac{63}{2420} to fractions with denominator 12100.

$$\frac{147}{12100}+\frac{315}{12100}+\frac{21}{605}$$

Since \frac{147}{12100} and \frac{315}{12100} have the same denominator, add them by adding their numerators.

$$\frac{147+315}{12100}+\frac{21}{605}$$

Add 147 and 315 to get 462.

$$\frac{462}{12100}+\frac{21}{605}$$

Reduce the fraction \frac{462}{12100} to lowest terms by extracting and canceling out 22.

$$\frac{21}{550}+\frac{21}{605}$$

Least common multiple of 550 and 605 is 6050. Convert \frac{21}{550} and \frac{21}{605} to fractions with denominator 6050.

$$\frac{231}{6050}+\frac{210}{6050}$$

Since \frac{231}{6050} and \frac{210}{6050} have the same denominator, add them by adding their numerators.

$$\frac{231+210}{6050}$$

Add 231 and 210 to get 441.

$$\frac{441}{6050}$$

Factor

$$\frac{3 ^ {2} \cdot 7 ^ {2}}{2 \cdot 5 ^ {2} \cdot 11 ^ {2}} = 0.07289256198347108$$