Solve 21*(1/7)^2-10*1/7

$$21 \cdot ( \frac { 1 } { 7 } ) ^ { 2 } - 10 \cdot \frac { 1 } { 7 }$$

Evaluate

$$-1$$

Solution Steps

Calculate \frac{1}{7} to the power of 2 and get \frac{1}{49}.

$$21\times \frac{1}{49}-10\times \frac{1}{7}$$

Multiply 21 and \frac{1}{49} to get \frac{21}{49}.

$$\frac{21}{49}-10\times \frac{1}{7}$$

Reduce the fraction \frac{21}{49} to lowest terms by extracting and canceling out 7.

$$\frac{3}{7}-10\times \frac{1}{7}$$

Multiply 10 and \frac{1}{7} to get \frac{10}{7}.

$$\frac{3}{7}-\frac{10}{7}$$

Since \frac{3}{7} and \frac{10}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-10}{7}$$

Subtract 10 from 3 to get -7.

$$\frac{-7}{7}$$

Divide -7 by 7 to get -1.

$$-1$$

Factor

$$-1$$