Solve 21:7+(5*1-2*2)^0+(5+10)^0

$$21 : 7 + ( 5 \times 1 - 2 \times 2 ) ^ { 0 } + ( 5 + 10 ) ^ { 0 }$$

Evaluate

$$5$$

Solution Steps

Divide 21 by 7 to get 3.

$$3+\left(5\times 1-2\times 2\right)^{0}+\left(5+10\right)^{0}$$

Multiply 5 and 1 to get 5.

$$3+\left(5-2\times 2\right)^{0}+\left(5+10\right)^{0}$$

Multiply 2 and 2 to get 4.

$$3+\left(5-4\right)^{0}+\left(5+10\right)^{0}$$

Subtract 4 from 5 to get 1.

$$3+1^{0}+\left(5+10\right)^{0}$$

Calculate 1 to the power of 0 and get 1.

$$3+1+\left(5+10\right)^{0}$$

Add 3 and 1 to get 4.

$$4+\left(5+10\right)^{0}$$

Add 5 and 10 to get 15.

$$4+15^{0}$$

Calculate 15 to the power of 0 and get 1.

$$4+1$$

Add 4 and 1 to get 5.

$$5$$

Factor

$$5$$