Solve 21/2+31/6-41/3

$$21 / 2 + 31 / 6 - 41 / 3$$

Evaluate

$$2$$

Solution Steps

Least common multiple of 2 and 6 is 6. Convert \frac{21}{2} and \frac{31}{6} to fractions with denominator 6.

$$\frac{63}{6}+\frac{31}{6}-\frac{41}{3}$$

Since \frac{63}{6} and \frac{31}{6} have the same denominator, add them by adding their numerators.

$$\frac{63+31}{6}-\frac{41}{3}$$

Add 63 and 31 to get 94.

$$\frac{94}{6}-\frac{41}{3}$$

Reduce the fraction \frac{94}{6} to lowest terms by extracting and canceling out 2.

$$\frac{47}{3}-\frac{41}{3}$$

Since \frac{47}{3} and \frac{41}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{47-41}{3}$$

Subtract 41 from 47 to get 6.

$$\frac{6}{3}$$

Divide 6 by 3 to get 2.

$$2$$

Factor

$$2$$