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20x+x^{2}-44=0
Subtract 44 from both sides.
x^{2}+20x-44=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=20 ab=-44
To solve the equation, factor x^{2}+20x-44 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
-1,44 -2,22 -4,11
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -44.
-1+44=43 -2+22=20 -4+11=7
Calculate the sum for each pair.
a=-2 b=22
The solution is the pair that gives sum 20.
\left(x-2\right)\left(x+22\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=2 x=-22
To find equation solutions, solve x-2=0 and x+22=0.
20x+x^{2}-44=0
Subtract 44 from both sides.
x^{2}+20x-44=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=20 ab=1\left(-44\right)=-44
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-44. To find a and b, set up a system to be solved.
-1,44 -2,22 -4,11
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -44.
-1+44=43 -2+22=20 -4+11=7
Calculate the sum for each pair.
a=-2 b=22
The solution is the pair that gives sum 20.
\left(x^{2}-2x\right)+\left(22x-44\right)
Rewrite x^{2}+20x-44 as \left(x^{2}-2x\right)+\left(22x-44\right).
x\left(x-2\right)+22\left(x-2\right)
Factor out x in the first and 22 in the second group.
\left(x-2\right)\left(x+22\right)
Factor out common term x-2 by using distributive property.
x=2 x=-22
To find equation solutions, solve x-2=0 and x+22=0.
x^{2}+20x=44
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x^{2}+20x-44=44-44
Subtract 44 from both sides of the equation.
x^{2}+20x-44=0
Subtracting 44 from itself leaves 0.
x=\frac{-20±\sqrt{20^{2}-4\left(-44\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 20 for b, and -44 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-20±\sqrt{400-4\left(-44\right)}}{2}
Square 20.
x=\frac{-20±\sqrt{400+176}}{2}
Multiply -4 times -44.
x=\frac{-20±\sqrt{576}}{2}
Add 400 to 176.
x=\frac{-20±24}{2}
Take the square root of 576.
x=\frac{4}{2}
Now solve the equation x=\frac{-20±24}{2} when ± is plus. Add -20 to 24.
x=2
Divide 4 by 2.
x=-\frac{44}{2}
Now solve the equation x=\frac{-20±24}{2} when ± is minus. Subtract 24 from -20.
x=-22
Divide -44 by 2.
x=2 x=-22
The equation is now solved.
x^{2}+20x=44
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+20x+10^{2}=44+10^{2}
Divide 20, the coefficient of the x term, by 2 to get 10. Then add the square of 10 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+20x+100=44+100
Square 10.
x^{2}+20x+100=144
Add 44 to 100.
\left(x+10\right)^{2}=144
Factor x^{2}+20x+100. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+10\right)^{2}}=\sqrt{144}
Take the square root of both sides of the equation.
x+10=12 x+10=-12
Simplify.
x=2 x=-22
Subtract 10 from both sides of the equation.