Solve 20x-19x+b^2+4=b^2

$$20 x - 19 x + b ^ { 2 } + 4 = b ^ { 2 }$$

Solve for x

$$x=-4$$

Steps for Solving Linear Equation

Combine 20x and -19x to get x.

$$x+b^{2}+4=b^{2}$$

Subtract b^{2} from both sides.

$$x+4=b^{2}-b^{2}$$

Combine b^{2} and -b^{2} to get 0.

$$x+4=0$$

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$x=-4$$

Solve for b (complex solution)

$$b\in \mathrm{C}$$

$$x=-4$$

Solve for b

$$b\in \mathrm{R}$$

$$x=-4$$