Solve for x
x\leq \frac{35}{2}
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1300+40x\leq 2000
Multiply 20 and 65 to get 1300.
40x\leq 2000-1300
Subtract 1300 from both sides.
40x\leq 700
Subtract 1300 from 2000 to get 700.
x\leq \frac{700}{40}
Divide both sides by 40. Since 40 is positive, the inequality direction remains the same.
x\leq \frac{35}{2}
Reduce the fraction \frac{700}{40} to lowest terms by extracting and canceling out 20.
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