Solve 20*1-0+3+10div12=

$$20 \times 1 - 0 + 3 + 10 \div 12 =$$

Evaluate

$$\frac{143}{6}\approx 23.833333333$$

Solution Steps

Multiply 20 and 1 to get 20.

$$20-0+3+\frac{10}{12}$$

Subtract 0 from 20 to get 20.

$$20+3+\frac{10}{12}$$

Add 20 and 3 to get 23.

$$23+\frac{10}{12}$$

Reduce the fraction \frac{10}{12} to lowest terms by extracting and canceling out 2.

$$23+\frac{5}{6}$$

Convert 23 to fraction \frac{138}{6}.

$$\frac{138}{6}+\frac{5}{6}$$

Since \frac{138}{6} and \frac{5}{6} have the same denominator, add them by adding their numerators.

$$\frac{138+5}{6}$$

Add 138 and 5 to get 143.

$$\frac{143}{6}$$

Factor

$$\frac{11 \cdot 13}{2 \cdot 3} = 23\frac{5}{6} = 23.833333333333332$$