Solve 20*1952=

$$20 \times 1952=$$

Evaluate

$$39040$$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}20\\\underline{\times\phantom{9}1952}\\\end{array}$$

Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 20 with 2. Write the result 40 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}20\\\underline{\times\phantom{9}1952}\\\phantom{\times999}40\\\end{array}$$

Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 20 with 5. Write the result 100 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}20\\\underline{\times\phantom{9}1952}\\\phantom{\times999}40\\\phantom{\times9}100\phantom{9}\\\end{array}$$

Now multiply the first number with the 3^{rd} digit in 2^{nd} number to get intermediate results. That is Multiply 20 with 9. Write the result 180 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}20\\\underline{\times\phantom{9}1952}\\\phantom{\times999}40\\\phantom{\times9}100\phantom{9}\\\phantom{\times}180\phantom{99}\\\end{array}$$

Now multiply the first number with the 4^{th} digit in 2^{nd} number to get intermediate results. That is Multiply 20 with 1. Write the result 20 at the end leaving 3 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}20\\\underline{\times\phantom{9}1952}\\\phantom{\times999}40\\\phantom{\times9}100\phantom{9}\\\phantom{\times}180\phantom{99}\\\underline{\phantom{\times}20\phantom{999}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}20\\\underline{\times\phantom{9}1952}\\\phantom{\times999}40\\\phantom{\times9}100\phantom{9}\\\phantom{\times}180\phantom{99}\\\underline{\phantom{\times}20\phantom{999}}\\\phantom{\times}39040\end{array}$$

Factor

$$2^{7}\times 5\times 61$$