Solve for x
x\leq -\frac{50}{11}
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300+22x\leq 200
Multiply 20 and 15 to get 300.
22x\leq 200-300
Subtract 300 from both sides.
22x\leq -100
Subtract 300 from 200 to get -100.
x\leq \frac{-100}{22}
Divide both sides by 22. Since 22 is positive, the inequality direction remains the same.
x\leq -\frac{50}{11}
Reduce the fraction \frac{-100}{22} to lowest terms by extracting and canceling out 2.
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