Solve 203/4-182/3

$$20 \frac { 3 } { 4 } - 18 \frac { 2 } { 3 }$$

Evaluate

$$\frac{25}{12}\approx 2.083333333$$

Solution Steps

Multiply 20 and 4 to get 80.

$$\frac{80+3}{4}-\frac{18\times 3+2}{3}$$

Add 80 and 3 to get 83.

$$\frac{83}{4}-\frac{18\times 3+2}{3}$$

Multiply 18 and 3 to get 54.

$$\frac{83}{4}-\frac{54+2}{3}$$

Add 54 and 2 to get 56.

$$\frac{83}{4}-\frac{56}{3}$$

Least common multiple of 4 and 3 is 12. Convert \frac{83}{4} and \frac{56}{3} to fractions with denominator 12.

$$\frac{249}{12}-\frac{224}{12}$$

Since \frac{249}{12} and \frac{224}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{249-224}{12}$$

Subtract 224 from 249 to get 25.

$$\frac{25}{12}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {2} \cdot 3} = 2\frac{1}{12} = 2.0833333333333335$$