Solve 201/2+(201/2-13/5)=

$$20 \frac { 1 } { 2 } + ( 20 \frac { 1 } { 2 } - 1 \frac { 3 } { 5 } ) =$$

Evaluate

$$\frac{197}{5}=39.4$$

Solution Steps

Multiply 20 and 2 to get 40.

$$\frac{40+1}{2}+\frac{20\times 2+1}{2}-\frac{1\times 5+3}{5}$$

Add 40 and 1 to get 41.

$$\frac{41}{2}+\frac{20\times 2+1}{2}-\frac{1\times 5+3}{5}$$

Multiply 20 and 2 to get 40.

$$\frac{41}{2}+\frac{40+1}{2}-\frac{1\times 5+3}{5}$$

Add 40 and 1 to get 41.

$$\frac{41}{2}+\frac{41}{2}-\frac{1\times 5+3}{5}$$

Since \frac{41}{2} and \frac{41}{2} have the same denominator, add them by adding their numerators.

$$\frac{41+41}{2}-\frac{1\times 5+3}{5}$$

Add 41 and 41 to get 82.

$$\frac{82}{2}-\frac{1\times 5+3}{5}$$

Divide 82 by 2 to get 41.

$$41-\frac{1\times 5+3}{5}$$

Multiply 1 and 5 to get 5.

$$41-\frac{5+3}{5}$$

Add 5 and 3 to get 8.

$$41-\frac{8}{5}$$

Convert 41 to fraction \frac{205}{5}.

$$\frac{205}{5}-\frac{8}{5}$$

Since \frac{205}{5} and \frac{8}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{205-8}{5}$$

Subtract 8 from 205 to get 197.

$$\frac{197}{5}$$

Factor

$$\frac{197}{5} = 39\frac{2}{5} = 39.4$$