Solve 20div4lfloor30(20-4*3)+6rfloor

$$20 \div 4 \lfloor 30(20-4 \times 3)+6 \rfloor$$

Evaluate

$$1230$$

Solution Steps

Divide 20 by 4 to get 5.

$$5\lfloor 30\left(20-4\times 3\right)+6\rfloor$$

Multiply 4 and 3 to get 12.

$$5\lfloor 30\left(20-12\right)+6\rfloor$$

Subtract 12 from 20 to get 8.

$$5\lfloor 30\times 8+6\rfloor$$

Multiply 30 and 8 to get 240.

$$5\lfloor 240+6\rfloor$$

Add 240 and 6 to get 246.

$$5\lfloor 246\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 246 is 246.

$$5\times 246$$

Multiply 5 and 246 to get 1230.

$$1230$$

Factor

$$2\times 3\times 5\times 41$$