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\frac{1}{5}x+\frac{5}{100}y=\frac{9}{100}\times 300
Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.
\frac{1}{5}x+\frac{1}{20}y=\frac{9}{100}\times 300
Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.
\frac{1}{5}x+\frac{1}{20}y=27
Multiply \frac{9}{100} and 300 to get 27.
\frac{1}{5}x=27-\frac{1}{20}y
Subtract \frac{1}{20}y from both sides.
\frac{1}{5}x=-\frac{y}{20}+27
The equation is in standard form.
\frac{\frac{1}{5}x}{\frac{1}{5}}=\frac{-\frac{y}{20}+27}{\frac{1}{5}}
Multiply both sides by 5.
x=\frac{-\frac{y}{20}+27}{\frac{1}{5}}
Dividing by \frac{1}{5} undoes the multiplication by \frac{1}{5}.
x=-\frac{y}{4}+135
Divide 27-\frac{y}{20} by \frac{1}{5} by multiplying 27-\frac{y}{20} by the reciprocal of \frac{1}{5}.
\frac{1}{5}x+\frac{5}{100}y=\frac{9}{100}\times 300
Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.
\frac{1}{5}x+\frac{1}{20}y=\frac{9}{100}\times 300
Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.
\frac{1}{5}x+\frac{1}{20}y=27
Multiply \frac{9}{100} and 300 to get 27.
\frac{1}{20}y=27-\frac{1}{5}x
Subtract \frac{1}{5}x from both sides.
\frac{1}{20}y=-\frac{x}{5}+27
The equation is in standard form.
\frac{\frac{1}{20}y}{\frac{1}{20}}=\frac{-\frac{x}{5}+27}{\frac{1}{20}}
Multiply both sides by 20.
y=\frac{-\frac{x}{5}+27}{\frac{1}{20}}
Dividing by \frac{1}{20} undoes the multiplication by \frac{1}{20}.
y=540-4x
Divide 27-\frac{x}{5} by \frac{1}{20} by multiplying 27-\frac{x}{5} by the reciprocal of \frac{1}{20}.