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400+x^{2}=24^{2}
Calculate 20 to the power of 2 and get 400.
400+x^{2}=576
Calculate 24 to the power of 2 and get 576.
x^{2}=576-400
Subtract 400 from both sides.
x^{2}=176
Subtract 400 from 576 to get 176.
x=4\sqrt{11} x=-4\sqrt{11}
Take the square root of both sides of the equation.
400+x^{2}=24^{2}
Calculate 20 to the power of 2 and get 400.
400+x^{2}=576
Calculate 24 to the power of 2 and get 576.
400+x^{2}-576=0
Subtract 576 from both sides.
-176+x^{2}=0
Subtract 576 from 400 to get -176.
x^{2}-176=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-176\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -176 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-176\right)}}{2}
Square 0.
x=\frac{0±\sqrt{704}}{2}
Multiply -4 times -176.
x=\frac{0±8\sqrt{11}}{2}
Take the square root of 704.
x=4\sqrt{11}
Now solve the equation x=\frac{0±8\sqrt{11}}{2} when ± is plus.
x=-4\sqrt{11}
Now solve the equation x=\frac{0±8\sqrt{11}}{2} when ± is minus.
x=4\sqrt{11} x=-4\sqrt{11}
The equation is now solved.