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20R^{2}=9\times 10^{9}\times 6\times 10^{-6}\times 3\times 10^{-6}
Variable R cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by R^{2}.
20R^{2}=9\times 10^{3}\times 6\times 3\times 10^{-6}
To multiply powers of the same base, add their exponents. Add 9 and -6 to get 3.
20R^{2}=9\times 10^{-3}\times 6\times 3
To multiply powers of the same base, add their exponents. Add 3 and -6 to get -3.
20R^{2}=9\times \frac{1}{1000}\times 6\times 3
Calculate 10 to the power of -3 and get \frac{1}{1000}.
20R^{2}=\frac{9}{1000}\times 6\times 3
Multiply 9 and \frac{1}{1000} to get \frac{9}{1000}.
20R^{2}=\frac{27}{500}\times 3
Multiply \frac{9}{1000} and 6 to get \frac{27}{500}.
20R^{2}=\frac{81}{500}
Multiply \frac{27}{500} and 3 to get \frac{81}{500}.
20R^{2}-\frac{81}{500}=0
Subtract \frac{81}{500} from both sides.
10000R^{2}-81=0
Multiply both sides by 500.
\left(100R-9\right)\left(100R+9\right)=0
Consider 10000R^{2}-81. Rewrite 10000R^{2}-81 as \left(100R\right)^{2}-9^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
R=\frac{9}{100} R=-\frac{9}{100}
To find equation solutions, solve 100R-9=0 and 100R+9=0.
20R^{2}=9\times 10^{9}\times 6\times 10^{-6}\times 3\times 10^{-6}
Variable R cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by R^{2}.
20R^{2}=9\times 10^{3}\times 6\times 3\times 10^{-6}
To multiply powers of the same base, add their exponents. Add 9 and -6 to get 3.
20R^{2}=9\times 10^{-3}\times 6\times 3
To multiply powers of the same base, add their exponents. Add 3 and -6 to get -3.
20R^{2}=9\times \frac{1}{1000}\times 6\times 3
Calculate 10 to the power of -3 and get \frac{1}{1000}.
20R^{2}=\frac{9}{1000}\times 6\times 3
Multiply 9 and \frac{1}{1000} to get \frac{9}{1000}.
20R^{2}=\frac{27}{500}\times 3
Multiply \frac{9}{1000} and 6 to get \frac{27}{500}.
20R^{2}=\frac{81}{500}
Multiply \frac{27}{500} and 3 to get \frac{81}{500}.
R^{2}=\frac{\frac{81}{500}}{20}
Divide both sides by 20.
R^{2}=\frac{81}{500\times 20}
Express \frac{\frac{81}{500}}{20} as a single fraction.
R^{2}=\frac{81}{10000}
Multiply 500 and 20 to get 10000.
R=\frac{9}{100} R=-\frac{9}{100}
Take the square root of both sides of the equation.
20R^{2}=9\times 10^{9}\times 6\times 10^{-6}\times 3\times 10^{-6}
Variable R cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by R^{2}.
20R^{2}=9\times 10^{3}\times 6\times 3\times 10^{-6}
To multiply powers of the same base, add their exponents. Add 9 and -6 to get 3.
20R^{2}=9\times 10^{-3}\times 6\times 3
To multiply powers of the same base, add their exponents. Add 3 and -6 to get -3.
20R^{2}=9\times \frac{1}{1000}\times 6\times 3
Calculate 10 to the power of -3 and get \frac{1}{1000}.
20R^{2}=\frac{9}{1000}\times 6\times 3
Multiply 9 and \frac{1}{1000} to get \frac{9}{1000}.
20R^{2}=\frac{27}{500}\times 3
Multiply \frac{9}{1000} and 6 to get \frac{27}{500}.
20R^{2}=\frac{81}{500}
Multiply \frac{27}{500} and 3 to get \frac{81}{500}.
20R^{2}-\frac{81}{500}=0
Subtract \frac{81}{500} from both sides.
R=\frac{0±\sqrt{0^{2}-4\times 20\left(-\frac{81}{500}\right)}}{2\times 20}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 20 for a, 0 for b, and -\frac{81}{500} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
R=\frac{0±\sqrt{-4\times 20\left(-\frac{81}{500}\right)}}{2\times 20}
Square 0.
R=\frac{0±\sqrt{-80\left(-\frac{81}{500}\right)}}{2\times 20}
Multiply -4 times 20.
R=\frac{0±\sqrt{\frac{324}{25}}}{2\times 20}
Multiply -80 times -\frac{81}{500}.
R=\frac{0±\frac{18}{5}}{2\times 20}
Take the square root of \frac{324}{25}.
R=\frac{0±\frac{18}{5}}{40}
Multiply 2 times 20.
R=\frac{9}{100}
Now solve the equation R=\frac{0±\frac{18}{5}}{40} when ± is plus.
R=-\frac{9}{100}
Now solve the equation R=\frac{0±\frac{18}{5}}{40} when ± is minus.
R=\frac{9}{100} R=-\frac{9}{100}
The equation is now solved.